代码格式化与美化工具

输入 · 原始查询语句

select u.id, u.email, count(o.id) as total_orders, sum(o.amount) as revenue from users u inner join orders o on u.id = o.user_id where u.status = 'active' and o.created_at >= '2025-01-01' group by u.id, u.email having count(o.id) > 5 order by revenue desc limit 25;

输出 · 关键字与子句规范对齐

SELECT
  u.id,
  u.email,
  count(o.id) AS total_orders,
  sum(o.amount) AS revenue
FROM
  users u
  INNER JOIN orders o ON u.id = o.user_id
WHERE
  u.status = 'active'
  AND o.created_at >= '2025-01-01'
GROUP BY
  u.id,
  u.email
HAVING
  count(o.id) > 5
ORDER BY
  revenue DESC
LIMIT
  25;

输入 · 压缩标记文本

<section class="profile-card"><header><h2 class="title">用户设置</h2><span class="badge active">专业版</span></header><div class="content"><p>管理您的账户订阅计划与安全配置。</p><button type="button" class="btn-primary">保存变更</button></div></section>

输出 · 层次化排版节点

<section class="profile-card">
  <header>
    <h2 class="title">用户设置</h2>
    <span class="badge active">专业版</span>
  </header>
  <div class="content">
    <p>管理您的账户订阅计划与安全配置。</p>
    <button type="button" class="btn-primary">保存变更</button>
  </div>
</section>

输入 · 不规范缩进源码

def calculate_metrics(records,threshold=0.85):
    result={'passed':[],'failed':[],'ratio':0.0}
    for item in records:
      score=item.get('score',0.0)
      if score>=threshold:
        result['passed'].append(item['id'])
      else:
        result['failed'].append(item['id'])
    total=len(records)
    result['ratio']=len(result['passed'])/total if total>0 else 0.0
    return result

输出 · 规范化 PEP 8 缩进

def calculate_metrics(records, threshold=0.85):
    result = {'passed': [], 'failed': [], 'ratio': 0.0}
    for item in records:
        score = item.get('score', 0.0)
        if score >= threshold:
            result['passed'].append(item['id'])
        else:
            result['failed'].append(item['id'])
    total = len(records)
    result['ratio'] = len(result['passed']) / total if total > 0 else 0.0
    return result